(5x^2+40x+75)/(x^2+3x-10)=0

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Solution for (5x^2+40x+75)/(x^2+3x-10)=0 equation:


D( x )

x^2+3*x-10 = 0

x^2+3*x-10 = 0

x^2+3*x-10 = 0

x^2+3*x-10 = 0

DELTA = 3^2-(-10*1*4)

DELTA = 49

DELTA > 0

x = (49^(1/2)-3)/(1*2) or x = (-49^(1/2)-3)/(1*2)

x = 2 or x = -5

x in (-oo:-5) U (-5:2) U (2:+oo)

(5*x^2+40*x+75)/(x^2+3*x-10) = 0

5*x^2+40*x+75 = 0

5*(x^2+8*x+15) = 0

x^2+8*x+15 = 0

DELTA = 8^2-(1*4*15)

DELTA = 4

DELTA > 0

x = (4^(1/2)-8)/(1*2) or x = (-4^(1/2)-8)/(1*2)

x = -3 or x = -5

5*(x+5)*(x+3) = 0

x^2+3*x-10 = 0

x^2+3*x-10 = 0

DELTA = 3^2-(-10*1*4)

DELTA = 49

DELTA > 0

x = (49^(1/2)-3)/(1*2) or x = (-49^(1/2)-3)/(1*2)

x = 2 or x = -5

(x+5)*(x-2) = 0

(5*(x+5)*(x+3))/((x+5)*(x-2)) = 0

( x+3 )

x+3 = 0 // - 3

x = -3

( x+5 )

x+5 = 0 // - 5

x = -5

x in { -5}

x = -3

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